Ng\u00e0y h\u00f4m nay, ch\u00fang t\u00f4i<\/strong> xin \u0111\u01b0\u1ee3c t\u1ed5ng h\u1ee3p cho anh em d\u00e2n ch\u01a1i nh\u1eefng ki\u1ebfn th\u1ee9c v\u1ec1 kh\u00e1i ni\u1ec7m, c\u00e1ch \u0111\u00e1nh v\u00e0 c\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 xi\u00ean quay<\/strong> chi ti\u1ebft nh\u1ea5t \u0111\u1ec3 anh em hi\u1ec3u r\u00f5 h\u01a1n v\u1ec1 h\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 \u0111\u1ec1 n\u00e0y nh\u00e9.<\/p>\n L\u00f4 xi\u00ean quay<\/strong> l\u00e0 m\u1ed9t c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1 \u0111\u01a1n gi\u1ea3n, \u0111\u00f3 l\u00e0 t\u1eadp h\u1ee3p c\u00e1c t\u1ed5 h\u1ee3p c\u1eb7p l\u00f4 xi\u00ean 2, xi\u00ean 3 v\u00e0 xi\u00ean 4, ch\u01a1i theo c\u00e1ch n\u00e0y anh em kh\u00f4ng c\u1ea7n ph\u1ea3i k\u1ec3 c\u00e1c c\u1eb7p l\u00f4 xi\u00ean m\u00e0 ch\u1ec9 c\u1ea7n ghi t\u00ean c\u00e1c con l\u00f4 \u0111\u1ec3 tr\u00e1nh nh\u1ea7m l\u1eabn, m\u1ea5t th\u1eddi gian m\u00e0 t\u1ea5t c\u1ea3 \u0111\u1ec1u c\u00f3 th\u1ec3 ng\u1ea7m hi\u1ec3u \u0111\u01b0\u1ee3c.<\/p>\n V\u00ed d\u1ee5: Anh em mu\u1ed1n \u0111\u00e1nh l\u00f4 xi\u00ean quay 01, 02, 03, 04 th\u00ec ta c\u00f3:<\/p>\n Kh\u00e1i ni\u1ec7m v\u00e0 c\u00e1ch ch\u01a1i.<\/p>\n<\/div>\n Xi\u00ean quay c\u00f3 nhi\u1ec1u h\u00ecnh th\u1ee9c \u0111\u00e1nh nh\u01b0 xi\u00ean quay 2, 3 v\u00e0 4. V\u1eady c\u1ee5 th\u1ec3 c\u1ee7a t\u1eebng c\u00e1ch \u0111\u00e1nh l\u00e0 nh\u01b0 th\u1ebf n\u00e0o? C\u00e1ch t\u00ednh ti\u1ec1n th\u1eafng ra l\u00e0m sao? M\u1eddi anh em theo d\u00f5i<\/p>\n L\u00f4 xi\u00ean quay 2 <\/strong>l\u00e0 t\u1ed5 h\u1ee3p c\u00e1c c\u1eb7p xi\u00ean 2 c\u00f3 trong b\u1ed9 s\u1ed1 m\u00e0 anh em mu\u1ed1n \u0111\u00e1nh. \u0110i\u1ec1u ki\u1ec7n \u0111\u1ec3 th\u1eafng l\u00e0 anh em ph\u1ea3i tr\u00fang c\u1ea3 2 con trong b\u1ed9 xi\u00ean th\u00ec m\u1edbi \u0111\u01b0\u1ee3c nh\u1eadn th\u01b0\u1edfng.<\/p>\n V\u00ed d\u1ee5:<\/p>\n L\u00f4 xi\u00ean quay 3<\/strong> l\u00e0 t\u1ed5 h\u1ee3p c\u00e1c c\u1eb7p xi\u00ean 3 c\u00f3 trong b\u1ed9 s\u1ed1 m\u00e0 anh em mu\u1ed1n \u0111\u00e1nh. N\u1ebfu anh em tr\u00fang c\u1ea3 3 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 3, tr\u01b0\u1ee3t 1 con tr\u00fang 2 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 2, tr\u01b0\u1ee3t 2 con th\u00ec anh em thua.<\/p>\n V\u00ed d\u1ee5:<\/p>\n L\u00f4 xi\u00ean quay 4<\/strong> l\u00e0 t\u1ed5 h\u1ee3p c\u00e1c c\u1eb7p xi\u00ean 4 c\u00f3 trong b\u1ed9 s\u1ed1 m\u00e0 anh em mu\u1ed1n \u0111\u00e1nh. N\u1ebfu tr\u00fang c\u1ea3 4 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 4, tr\u01b0\u1ee3t 2 con tr\u00fang 2 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 2, tr\u01b0\u1ee3t 1 con tr\u00fang 3 con th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 \u0103n xi\u00ean 3, tr\u01b0\u1ee3t 3 con th\u00ec anh em thua.<\/p>\n V\u00ed d\u1ee5:<\/p>\n Kh\u00e1c v\u1edbi l\u00f4 xi\u00ean th\u00f4ng th\u01b0\u1eddng, ch\u01a1i xi\u00ean quay s\u1ebd c\u00f3 c\u00e1ch t\u00ednh ti\u1ec1n kh\u00e1c m\u1ed9t ch\u00fat do m\u1ed7i con xi\u00ean \u0111\u01b0\u1ee3c quy\u1ec1n tr\u01b0\u1ee3t 1 ho\u1eb7c 2 con s\u1ed1 th\u00e0nh \u0103n xi\u00ean 2, xi\u00ean 3.<\/p>\n T\u00f4i s\u1ebd t\u1ed5ng h\u1ee3p cho anh em c\u00e1ch t\u00ednh ti\u1ec1n xi\u00ean quay m\u1ed9t c\u00e1ch d\u1ec5 d\u00e0ng nh\u1ea5t \u0111\u1ec3 mang l\u1ea1i l\u1ee3i nhu\u1eadn c\u1ef1c cao cho anh em, tr\u00e1nh thi\u1ebfu hi\u1ec3u bi\u1ebft m\u00e0 m\u1ea5t ti\u1ec1n oan.<\/p>\n L\u00f4 xi\u00ean quay 2, 3, 4 \u0103n \u0111\u01b0\u1ee3c bao nhi\u00eau ti\u1ec1n?<\/p>\n<\/div>\n L\u00f4 xi\u00ean 2 th\u00f4ng th\u01b0\u1eddng t\u1ef7 l\u1ec7 anh em tr\u00fang s\u1ebd l\u00e0 1 \u0103n 10.<\/p>\n V\u00ed d\u1ee5: Xi\u00ean quay 2 (01, 02, 03) s\u1ebd c\u00f3 3 c\u1eb7p xi\u00ean 2, anh em c\u01b0\u1ee3c 10.000\u0111 th\u00ec t\u1ed5ng ti\u1ec1n anh em ph\u1ea3i tr\u1ea3 l\u00e0 30.000\u0111. Tr\u00fang 1 c\u1eb7p xi\u00ean 2 th\u00ec anh em \u0103n 100.000\u0111, 2 c\u1eb7p xi\u00ean 2 th\u00ec \u0103n 200.000\u0111.<\/p>\n L\u00f4 xi\u00ean 3 th\u00f4ng th\u01b0\u1eddng th\u00ec t\u1ef7 l\u1ec7 anh em tr\u00fang s\u1ebd l\u00e0 1 \u0103n 40 (t\u00f9y nh\u00e0 c\u00e1i).<\/p>\n V\u00ed d\u1ee5: Anh em \u0111\u00e1nh xi\u00ean quay 3 c\u1ee7a b\u1ed9 s\u1ed1 (01, 02, 03, 04) s\u1ebd c\u00f3 4 c\u1eb7p xi\u00ean 3, \u0111\u00e1nh 10.000\u0111 th\u00ec t\u1ed5ng ti\u1ec1n ph\u1ea3i tr\u1ea3 l\u00e0 40.000\u0111.<\/p>\n Tr\u00fang 1 c\u1eb7p xi\u00ean 3 th\u00ec \u0103n 400.000\u0111, 2 c\u1eb7p xi\u00ean 3 th\u00ec \u0103n 800.000\u0111. Tr\u01b0\u1eddng h\u1ee3p tr\u01b0\u1ee3t 1 con tr\u00fang 2 con l\u00f4 th\u00ec \u0103n con xi\u00ean 2 (t\u00ednh ti\u1ec1n nh\u01b0 tr\u00ean).<\/p>\n L\u00f4 xi\u00ean 4 th\u00f4ng th\u01b0\u1eddng th\u00ec t\u1ef7 l\u1ec7 anh em tr\u00fang s\u1ebd l\u00e0 1 \u0103n 100 (t\u00f9y nh\u00e0 c\u00e1i).<\/p>\n V\u00ed d\u1ee5: Anh em \u0111\u00e1nh xi\u00ean quay 4 c\u1ee7a b\u1ed9 s\u1ed1 (01, 02, 03, 04, 05) s\u1ebd c\u00f3 5 c\u1eb7p xi\u00ean 4, \u0111\u00e1nh 10.000\u0111 th\u00ec t\u1ed5ng v\u1ed1n l\u00e0 50.000\u0111.<\/p>\n Tr\u00fang 1 c\u1eb7p xi\u00ean 4 th\u00ec \u0103n 1.000.000\u0111, 2 c\u1eb7p xi\u00ean 4 th\u00ec \u0103n 2.000.000\u0111. Tr\u01b0\u1eddng h\u1ee3p tr\u01b0\u1ee3t 1 con tr\u00fang 3 con l\u00f4 th\u00ec \u0103n con xi\u00ean 3 (t\u00ednh ti\u1ec1n nh\u01b0 xi\u00ean 3), tr\u01b0\u1ee3t 2 con tr\u00fang 2 con l\u00f4 th\u00ec \u0103n con xi\u00ean 2 (t\u00ednh ti\u1ec1n nh\u01b0 xi\u00ean 2).<\/p>\n T\u1ed5ng h\u1ee3p nh\u1eefng th\u00f4ng tin v\u1ec1 l\u00f4 xi\u00ean quay l\u00e0 g\u00ec<\/strong>? C\u00e1ch \u0111\u00e1nh v\u00e0 t\u00ednh ti\u1ec1n chi ti\u1ebft t\u1eebng lo\u1ea1i l\u00f4 \u0111\u1ec1 g\u1eedi \u0111\u1ebfn anh em, hy v\u1ecdng r\u1eb1ng c\u00e1c chuy\u00ean gia c\u1ee7a ch\u00fang t\u00f4i s\u1ebd gi\u00fap anh em ti\u1ebfp thu th\u00eam nhi\u1ec1u kinh nghi\u1ec7m cho m\u00ecnh.<\/p>\n Ch\u00fac anh em s\u1ebd h\u1ed1t th\u1eadt nhi\u1ec1u b\u1ea1c t\u1eeb c\u00e1ch ch\u01a1i n\u00e0y.<\/p>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\nL\u00f4 xi\u00ean quay l\u00e0 g\u00ec?<\/span><\/h2>\n
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\u0110\u00e1nh l\u00f4 xi\u00ean quay nh\u01b0 th\u1ebf n\u00e0o?<\/span><\/h2>\n
C\u00e1ch \u0111\u00e1nh xi\u00ean quay 2<\/span><\/h3>\n
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C\u00e1ch ch\u01a1i xi\u00ean quay 3<\/span><\/h3>\n
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L\u00f4 xi\u00ean quay 4 c\u00f3 bao nhi\u00eau c\u1eb7p?<\/span><\/h3>\n
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C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 xi\u00ean quay<\/span><\/h2>\n
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L\u00f4 xi\u00ean quay 2 \u0103n bao nhi\u00eau ti\u1ec1n?<\/span><\/h3>\n
L\u00f4 xi\u00ean quay 3 \u0103n bao nhi\u00eau?<\/span><\/h3>\n
L\u00f4 xi\u00ean quay 4 \u0103n bao nhi\u00eau?<\/span><\/h3>\n
K\u1ebft lu\u1eadn<\/span><\/h2>\n
SOI C\u1ea6U MI\u1ec0N B\u1eaeC CAO C\u1ea4P<\/strong><\/span><\/h4>\n